Good morning sir.Beats application sir .Explain fastly sir.
raju nagula , 6 Years ago
Grade
Electrostatics> Good morning sir. Beats application sir ....
1 Answers
Arun
Last Activity: 6 Years ago
Dear student
frequency of unknown tuning fork will be = 288 +4 = 292 Hz or 288 – 4 = 284 Hz
on placing a little wax on unknown tuning fork, its frequency decreases but now the number of beats produced is 2 i.e. the frequency difference now decreases. It is possible when frequency of unknown tuning fork = 292 Hz
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