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Electrostatics

Good evening sir.
Beats application problem.
Explain how to write formula. And explain solution.

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Profile image of raju nagula
8 Years agoGrade
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1 Answer

Profile image of Arun
8 Years ago
 
There are 5 beats between A&B.
Hence possible frequency of A =  512 ± 5  = 507 or 517.
 
When one prong of A is filled, its frequency becomes greater than the original frequency.
 
Hence 517 Hz is correct.
 
Hope it helps.
 
Regards
Arun (askIITians forum expert)