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A string is stretched between fixed points separated by 75 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is :-

anashwara , 5 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 5 Years ago

Dear student
Given nv/2l=315 and (n+1)v/2l=420
by solving the above equations we get v/2l=105 hz
 
Regards
Arun (askIITians forum expert)

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