0

Guest

Courses New

Prove that the line x − 2y + 4a = 0 touches the parabola y2 = 4ax, and find the coordinates of P, the point of contact. If the line x−2y +2a = 0 meets the parabola in Q, R, and M is the mid-point of QR, prove that PM is parallel to the axis of x, and that this axis and the line through M perpendicular to it meet on the normal at P to the parabola.

Prove that the line x − 2y + 4a = 0 touches the parabola y2 = 4ax, and find the
coordinates of P, the point of contact. If the line x−2y +2a = 0 meets the parabola
in Q, R, and M is the mid-point of QR, prove that PM is parallel to the axis of x,
and that this axis and the line through M perpendicular to it meet on the normal at
P to the parabola.
 

Grade:12

1 Answers

Arun
25757 Points
3 years ago
Dear student
 
x - 2y  +4a = 0
 
y = ½ x + 2a
 
Now c = 2a
Also a/m = a/(1/2) = 2a
 
Since c = a/m
Hence line is a tangent
 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Vectors

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More