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In abcdef is a regular hexagon in which AB=a ,BC=b then AE=? In abcdef is a regular hexagon in which AB=a ,BC=b then AE=?
HereAB→=a→andBC→=b→AsfromthefigureCDisparalleltoFAbutintheoppositedirection so,CD→=-AB→=-a→DEisparalleltoABbutintheoppositedirectionso,DE→=-AB→=-b→FBistheresultantofthevectorFA andABso,FB=VectorsumofFAandAB=a→+b→Weknowthatinaregularhexagon,AD=2BCso,AD→=2b→Andweknowthat,AC→+CD→=AD→SoCD→=2b→-a→-b→=b→-a→SinceAF→=-CD→so,AF→=a→-b→AndweknowthatAD→+DE→=AE→AE→=2b→-a→
HereAB→=a→andBC→=b→
AsfromthefigureCDisparalleltoFAbutintheoppositedirection so,CD→=-AB→=-a→
DEisparalleltoABbutintheoppositedirectionso,DE→=-AB→=-b→FBistheresultantofthevectorFA andABso,FB=VectorsumofFAandAB=a→+b→Weknowthatinaregularhexagon,AD=2BCso,AD→=2b→Andweknowthat,AC→+CD→=AD→SoCD→=2b→-a→-b→=b→-a→
SinceAF→=-CD→so,AF→=a→-b→AndweknowthatAD→+DE→=AE→AE→=2b→-a→
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