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If ABCDEF is a regular hexagon and vectors AB+AC+AD+AE+AF=xAD,then x=
Dear pallavi
AB+AC+AD+AE+AF=xAD
we know
AB=ED and AF =CD
so (ED +AE) +AD + (CD+AC) =xAD
AD +AD + AD =xAD
x=3
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Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best. Regards,Askiitians ExpertsBadiuddin
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