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prove that any two edges in a regular tetrahedron are perpendicular.
Dear jimmy singh
her O is origin
OA=OB=OC=AB=BC=CA
Now AB=BC=CA
|AB|2=|BC|2=|CA|2
|b-a|2 =|c-a|2=|a-c|2
here a,b,c are position vector of A,B,C
|a|2 +|b|2 -2a.b =|b|2 +|c|2 -2c.b=|a|2 +|c|2 -2a.c
or a.b=b.c=c.a
or a.b=b.c
or b.(a-c)=0
OB.AC=0
OB is perpendicular to AC
similerly for others
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