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all (A to Z) formula of vector for class 11


8 years ago

Aman Bansal
592 Points
							Dear Shubham,
The formula for the length of a 2D vector is the Pythagorean Formula. Say that the vector is represented by   (x, y)T.   Put the vector with its tail at the origin. Now make a triangle by drawing the two sides:
side_1   =  (x, 0)T

side_2   = (0, y)T.

The length of side_1 is x, and the length of side_2 is y, so:

length (x, y)T   =    ( x2 + y2 )

In this formula,    means the positive square root. We don''t (of course) want the length to be negative.
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Aman Bansal


8 years ago
Aman Bansal
592 Points
							Dear Shubham,
vector quantity has both magnitude and direction. Acceleration, velocity, force and displacement are all examples of vector quantities. A scalar quantity is has only magnitude (so the direction is not important). Examples include speed, time and distance.
Unit Vectors
A unit vector is a vector which has a magnitude of 1. There are three important unit vectors which are commonly used and these are the vectors in the direction of the x, y and z-axes. The unit vector in the direction of the x-axis is i, the unit vector in the direction of the y-axis is j and the unit vector in the direction of the z-axis is k.
Writing vectors in this form can make working with vectors easier.
The Magnitude of a Vector
The magnitude of a vector can be found using Pythagoras''s theorem.

The magnitude of ai + bj = √(a2 + b2)

We denote the magnitude of the vector a by | a |
Position Vectors
Position vectors are vectors giving the position of a point, relative to a fixed point (the origin).
For example, the points A, B and C are the vertices of a triangle, with position vectors a, b and c respectively:

You can draw in the origin wherever you want.
Notice that  = - a + b = b - a because you can get from A to B by going from A to O and then going from O to B.
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So start the brain storming…. become a leader with Elite Expert League ASKIITIANS
Thanks
Aman Bansal


8 years ago
Sorabh Gulia
23 Points
							Vector FormulasA vector can also be defined as an element of a vector space.  Vectors are sometimes referred to by the number of coordinates they have, so a 2-dimensional vector  is often called a two-vector, an n-dimensional vector is often called an n-vector, and so on.The important formulas of vectors are given below: 1. The position vector of any point p(x,y) is$op = \dbinom{x}{y}$ or OP = ( x,y ). 2.The magnitude of position vector$OP = \sqrt{x^2 + y^2}$ and direction $\tan \theta = \dfrac{y}{x}$ 3. The unit vector = $\dbinom{1}{0}$ where the magnitude of unit vector is 1Or,the unit vector = $\dfrac{vector}{its modulus} = \dfrac{ \overrightarrow{a}}{ |\overrightarrow{a}| }$ 4.The two vectors $\overrightarrow{a}$ and $\overrightarrow{b}$ are parallel if $\overrightarrow{a} = k \overrightarrow{b}$ and $\overrightarrow{b} = m \overrightarrow{a}$ where k and m are the scalars. 5.If $\overrightarrow{AB} + \overrightarrow{BC} = \overrightarrow{AC}$ then $\overrightarrow{AC}$ is the result vector which is the triangle law of vector addition. 6. The scalar or dot product of any two vectors $\overrightarrow{a} . \overrightarrow{b} = | \overrightarrow{a} | | \overrightarrow{b} | cos\theta$. 7. The angle between two vectors is $\cos \theta = \dfrac{\overrightarrow{a} . \overrightarrow{b}} {| \overrightarrow{a} | | \overrightarrow{b} |}$ 8. $\overrightarrow{a} = x_1 i + y_1 j$ and $\overrightarrow{b} = x_2 i + y_2 j$ , then :$\overrightarrow{a} . \overrightarrow{b} = x_1 . x_2 + y_1 . y_2$ where $i.j = j.1 = 0$ 9. If the position vector of A is $\overrightarrow{a}$ , position vector of point B is $\overrightarrow{b}$ and position vector of mid-point M is m then $\overrightarrow{m} = \dfrac{\overrightarrow{a} + \overrightarrow{b}}{2}$ 10. If the point P divides Ab internally in the ratio m:n then position vector of P is given by $\overrightarrow{p} = \dfrac{n \overrightarrow{a} + m \overrightarrow{b}}{m + n}$ which is a section formula. 11.If P divides AB externally in the ratio m:n then $\overrightarrow{p} = \dfrac{m \overrightarrow{b} - n \overrightarrow{a}}{m - n}$PRODUCT OF TWO VECTORS 1.Scalar Product ( dot product ) Let $\overrightarrow{a} = (a_1,a_2) , \overrightarrow{b} = (b_1,b_2)$ then dot product of $\overrightarrow{a}$ & $\overrightarrow{b}$ is devoted by $\overrightarrow{a}.\overrightarrow{b}$ read as $\overrightarrow{a}$ dot $\overrightarrow{b}$ and defined by $\overrightarrow{a}.\overrightarrow{b} = a_1 b_1 , a_2 b_2$ Note:if$\overrightarrow{a} = (a_1,a_2,a_3),\overrightarrow{b} = (b_1,b_2,b_3) \\ \overrightarrow{a} . \overrightarrow{b} = a_1b_1 + a_2b_2 +a_3b_3$ OR The scalar product of $\overrightarrow{a}$ & $\overrightarrow{b}$ is devoted by $\overrightarrow{a} . \overrightarrow{b}$ ,$\overrightarrow{a} . \overrightarrow{b} |\overrightarrow{a}|.|\overrightarrow{b}| \cos \theta$ where $\theta$ being  angle between $\overrightarrow{a}$ & $\overrightarrow{b}$ Note:1$\cos \theta = \dfrac{\overrightarrow{a} . \overrightarrow{b}}{| \overrightarrow{a} | | \overrightarrow{b} |}$Note:2$\overrightarrow{a}$ & $\overrightarrow{b}$ are perpendicular if $\theta$ = $90^o$i.e $\overrightarrow{a} . \overrightarrow{b} |\overrightarrow{a}|.|\overrightarrow{b}| \cos 90^o$ or $\overrightarrow{a} . \overrightarrow{b} = 0$ 2.Properties of Scalar Producti. $\overrightarrow{a} . \overrightarrow{b} = \overrightarrow{b} . \overrightarrow{a}$.ii. $m \overrightarrow{a} . n \overrightarrow{b} - mn \overrightarrow{a}. \overrightarrow{b} = \overrightarrow{a} mn \overrightarrow{b}$.iii. $\overrightarrow{a}( \overrightarrow{b} + \overrightarrow{c} ) = \overrightarrow{a} . \overrightarrow{c}$iv. $( \overrightarrow{b} + \overrightarrow{c} )^2 = \overrightarrow{a}^2 + 2.\overrightarrow{a}.\overrightarrow{b} + \overrightarrow{b}^2$v. If $\overrightarrow{i} = (1,0,0): \overrightarrow{j} = (0,1,0), \overrightarrow{k} = (0,0,1)$then $\overrightarrow{i} . \overrightarrow{j} = \overrightarrow{j} . \overrightarrow{k} = \overrightarrow{k} . \overrightarrow{i} = \overrightarrow{i} . \overrightarrow{k} = \overrightarrow{j} . \overrightarrow{k} = 0$ 3.Vector (cross) Product of two vectors.Let $\overrightarrow{a} = (a_1 , a_2 , a_3 ), \overrightarrow{b} = (b_1 , b_2 , b_3 )$ be two vectors then the cross product of $\overrightarrow{a} \times \overrightarrow{b}$is devoted by$\overrightarrow{a} \times \overrightarrow{b}$ and defined by$\overrightarrow{a} \times \overrightarrow{b} = (a_1 , a_2 , a_3 ) \times (b_1 , b_2 , b_3 )$ $= \begin{pmatrix} a_1 & a_2 & a_3 & a_1 & a_2 \\ b_1 & b_2 & b_3 & b_1 & b_2 \end{pmatrix}$ = $( a_2 b_3 - a_3 b_2 , a_3 b_1 - a_1 b_2 - a_2 b_1 )$ We can define in terms of determinants as follows $\overrightarrow{a} \times \overrightarrow{b}$ = $\begin{vmatrix} \overrightarrow{i} & \overrightarrow{j} & \overrightarrow{k} \\ a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \end{vmatrix}$ $= ( a_2 b_3 - a_3 b_2 ) \overrightarrow{i} + ( a_3 b_1 - a_1 b_3 ) \overrightarrow{j} + ( a_1 b_2 - a_2 b_1 ) \overrightarrow{k}$Note:1               $| \overrightarrow{a} \times \overrightarrow{b} | = | \overrightarrow{a} | \times | \overrightarrow{b} | \sin \theta , \theta$ being angle between$\overrightarrow{a}$ & $\overrightarrow{b}$Note:2               $\dfrac{| \overrightarrow{a} \times \overrightarrow{b}| }{| \overrightarrow{a} | | \overrightarrow{b} | \sin \theta }$Note:3               If $\theta = 0$ , the $| \overrightarrow{a} \times \overrightarrow{b} | = 0 i.e \overrightarrow{a} \times \overrightarrow{b} = 0$ and $\overrightarrow{a}$ & $\overrightarrow{b}$ are parallel if $\overrightarrow{a} \times \overrightarrow{b} = 0$. 4. Properties of cross product i. $\overrightarrow{a} \times \overrightarrow{b} = 0$ii. $\overrightarrow{a} \times \overrightarrow{b} = \overrightarrow{b} \times \overrightarrow{a}$iii. $\overrightarrow{a} \times ( \overrightarrow{b} + \overrightarrow{c} ) = \overrightarrow{a} \times \overrightarrow{b} + \overrightarrow{a} \times \overrightarrow{c}$iv. $( n \overrightarrow{a} ) \times \overrightarrow{b} = n( \overrightarrow{a} \times \overrightarrow{b} ) \times n \overrightarrow{b}$v. $\overrightarrow{a} \times \overrightarrow{b}$ is perpendicular to both $\overrightarrow{a}$ and $\overrightarrow{b}$vi. $| \overrightarrow{a} \times \overrightarrow{b} |$ is a Area of paralelogram with sides $\overrightarrow{a}$ and $\overrightarrow{b}$vii. $\dfrac{1}{2} | \overrightarrow{a} \times \overrightarrow{b} + \overrightarrow{b} \times \overrightarrow{c} + \overrightarrow{c} \times \overrightarrow{a} |$ = area of triangle having $\overrightarrow{a}$ , $\overrightarrow{b}$ , $\overrightarrow{c}$ as position vectors of vertices of a triangle.

3 years ago
Ajeet Tiwari
85 Points
							hello studentshope it helpsthankyou

4 months ago
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