two vectors A and B have magnitude 2 and 1 respectively. if the angle between A and B is 60 degree then the vector A/2-B is

A/2-B = (A/2) + (-B)

R = √((A/2) ² +B² + 2(A/2)BCos(120))

A/2 = 1

B = 1

Cos120 = -1/2

R = 1
AT AN ANGLE OF = TAN^-1 ((ASin60)/(B-ACos60))
AT AN ANGLE OF 90° FROM (-B) OR B

Dear Naba

Given |A|=2 |B|=1

angle between A and B =60

Now call vector A/2 as C

|C|=|A|/2=1

and angle between B and C will be the same as that between A and B

|C-B|=√|c|² + |B|² -2|C||B|cos 60°

        =√1+1-1=1

As it is clear from the diagram C-B will be along angle bisector of -B and C so angle between C and A=60°

ALL THE BEST

Abhinav Batra