Y=sinx+cos2xaskiitians.com0Home » Forum » Trigonometry » Cos 2 76deg + Cos 2 14deg...Abhinav AcharyaCos276deg + Cos214deg -cos76deg.cos16deg.=2 years agoAnswer This QuestionAnswers : (1)Rinkoo GuptaAskIITians Faculty80 Pointscos276+cos214-cos76cos16(1+cos152)/2+(1+cos28)/2-cos76cos16=1+1/2[cos(180-28)+cos28]-cos76cos16=1+1/2[-cos28+cos28]-cos76cos16=1-cos76cos16=1-1/2[2cos76cos16]=1-1/2[cos92+cos60]=1-1/2[cos(90+20+1/2]=1-1/2[-sin2+1/2]=1-1/4+1/2 sin2=3/4+(1/2) sin2Thanks & RegardsRinkoo GuptaAskIITians Faculty2 years agoPost Your AnswerEnter your answer here... AnswerOther Related Questions on TrigonometryRelated QuestionA+B+C=180 PROVE THAT sin2 A-sin2 B-sin2 C=-2cosAsinBsinCThanx=(Sin y-cos y)/(siny +cosy ) then siny+ cosy,................Please give me a step wise solution of question with each & every reason From 2nd eq in question...-> ax sinß / cos²ß = by cosß / sin²ß…-> tan³ß = by / ax-> tanß = (by/ax)⅓...From tanß you can take out sinß and cos ß which are respectively:::: sinß = (by)⅓ /...Faiz 2 months ago Correction for the last step::-> [ (by)⅔ + (ax)⅔ ] ^3/2( instead of 2/3 wrongly printed ) = a² - b²....-> (by)⅔ + (ax)⅔ = ( a² - b ) ^ 2/3......Hence proved...Sorry the powers were wrongly...Faiz 2 months agoshow that 2 sinx+ 2 cosx >2 1 -1/square root 2 2)if tana and tan b are theroots of equation x 2 +px+qthen1) sin (a+b)=-p 2)tan(a+b)=p/q-1 3)cos a+b)1-q U must know the range of sinx and cosx. similarly sinx lessthan equal to 2 and greater than equal to ½.................(1) 1/2 > = 2^cosx > = 2.............(2) remember cosx is decreasing...Vikas TU 5 months agoif A+B=pi/2, where A,B>0, then the maimum value of sinA + sinB is equal to Hy darshini A+B=pi/2... Therefore A=pi/2 - B.. We have to max value of SinA+SinB.. Putting tha above value it comes SinA+CosB whose maximum value is 1/root 2.. Hope U like it..Suraj Singh 3 days agoView all Questions »Complete JEE Main/Advanced Course and Test SeriesOFFERED PRICE: R 15,000View DetailsGet extra R 3,000 offUSE CODE: MOB20Ask ExpertsHave any Question? Ask ExpertsTrigonometryAttached Image :- IMG-20170113-WA... Attach Image
Vineet Kumar , 7 Years ago
Grade 12
1 Answers
SAHIL
Last Activity: 7 Years ago
SORRY THE DOUBT IS UNCLEAR AND WE CANNOT UNDERSTAND IT
SO PLEASE POST IT AGAIN
THANKS
HOPE TO HEAR FROM YOUR SIDE AGAIN
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free