xcosc/a+ysinc/b=1 & ax/cosc-by/sinc=a^2-b^2 then prove x^2/a^2+y^2/b^2=1

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Saurabh Koranglekar · Answer

Dear student The question contains part as cos ( c/a) for sine angles Kindly check and upload proper question Regards

Vikas TU · Answer

Dear student Question is not clear Please attach an image, We will happy to help you Good Luck Cheers

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xcosc/a+ysinc/b=1 & ax/cosc-by/sinc=a^2-b^2 then prove x^2/a^2+y^2/b^2=1

xcosc/a+ysinc/b=1 & ax/cosc-by/sinc=a^2-b^2 then prove x^2/a^2+y^2/b^2=1

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xcosc/a+ysinc/b=1 & ax/cosc-by/sinc=a^2-b^2 then prove x^2/a^2+y^2/b^2=1

xcosc/a+ysinc/b=1 & ax/cosc-by/sinc=a^2-b^2 then prove x^2/a^2+y^2/b^2=1

2 Answers

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