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x + 1) = 3 has the general solution: 3 x – cos x sin 3 The equation 4 ( sin x cos (n pi / 4) + ( 8 /pi) ( n pi/ 2) + ( 3 pi /8) n pi (+/– ) (5 pi / 8) (n pi/4) + ( 7 pi / 4) 4 sin x cos x (cos^2 x – sin^2 x) = 3 – 4 2 sin 2x cos 2x = – 1 sin 4x = – 1 ( i got it till here but how is below equation dervied) 4x = 2n * pi + 3pi/2

x + 1) = 3 has the general solution:3x – cos x sin3The equation 4 ( sin x cos
  1. (n pi / 4) + ( 8 /pi)
  2. ( n  pi/ 2) + ( 3 pi /8)
  3.  n pi (+/– ) (5 pi / 8)
  4. (n pi/4) + ( 7 pi / 4) 
  5.    
    4 sin x cos x (cos^2 x – sin^2 x) = 3 – 4
     
    2 sin 2x cos 2x = – 1
     
    sin 4x = – 1
     
    ( i got it till here but how is below equation dervied)
     
    4x = 2n * pi + 3pi/2 
  6.  

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear Meghana
 
sin4x = – 1
 
or you can say 
 
4x = n* pi + (-1)^n * 3 pi/2
 
but when you put n as even and odd and if you combine those two
 
you will get 
 
4x = 2 n pi + 3 * pi/2

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