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```
x + 1) = 3 has the general solution: 3 x – cos x sin 3 The equation 4 ( sin x cos (n pi / 4) + ( 8 /pi) ( n pi/ 2) + ( 3 pi /8) n pi (+/– ) (5 pi / 8) (n pi/4) + ( 7 pi / 4) 4 sin x cos x (cos^2 x – sin^2 x) = 3 – 4 2 sin 2x cos 2x = – 1 sin 4x = – 1 ( i got it till here but how is below equation dervied) 4x = 2n * pi + 3pi/2

```
2 years ago

Arun
25768 Points
```							Dear Meghana sin4x = – 1 or you can say  4x = n* pi + (-1)^n * 3 pi/2 but when you put n as even and odd and if you combine those two you will get  4x = 2 n pi + 3 * pi/2
```
2 years ago
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Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions