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`        why tanx/2.cotx/2 is not equal to 1 when x= 0 and if equal then see my attached image`
4 months ago

1672 Points
```							first of all your ques is wrong. we have to find tanx/2.coty/2 and not tanx/2.cotx/2. you can apply componendo and dividendo, and then use the formula (1 – cosz)/(1+cosz)= tan^2(z/2). thence you will obtain the answer root3.now coming to why your method is wrong.when x=0, obviously x/2 is also zero.so tan(x/2) is also zero.but cotx/2 is not defined at x/2=0because it becomes infinity which is not a real number.it is because cot(theta)= cos(theta)/sin(theta), and when theta is zero, sintheta is also zero and division by zero is not allowed (or defined).kindly approve :)
```
4 months ago
Saurabh Koranglekar
3160 Points
```							Dear studentKindly upload complete question, otherwise tan a *cot a = 1 always except 0 and 90 degreesRegards
```
4 months ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions