What is the range of f(x)= 3|sinx|-2|cosx| ? What is the step to solve it?
Sunil Kumar , 7 Years ago
Grade
1 Answers
Arun
Last Activity: 7 Years ago
Dear Sunil
Since |.| mod operator is used maximum and minimum values of both sine and cosine are 1 and 0. But we know that when sine is max, cosine is min which is justified by sin^2(x) + cos^2(x) = 1 So answer to your question is [-2, 3]
Regards
Arun (askIITians forum expert)
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