Trigonometry
What is the range of f(x)= 3|sinx|-2|cosx| ? What is the step to solve it?
1 Answer
Arun
Dear Sunil
Since |.| mod operator is used maximum and minimum values of both sine and cosine are 1 and 0.
But we know that when sine is max, cosine is min which is justified by
sin^2(x) + cos^2(x) = 1
So answer to your question is [-2, 3]
But we know that when sine is max, cosine is min which is justified by
sin^2(x) + cos^2(x) = 1
So answer to your question is [-2, 3]
Regards
Arun (askIITians forum expert)
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