Trigonometry> What is componendo and dividendo, how do ...

What is componendo and dividendo, how do we apply this in different fields of mathematics?

Garima , 8 Years ago

Grade 11

2 Answers

Himanshu

Last Activity: 8 Years ago

Componendo and dividendo are just a part of the mathematics calculation.

Componendo and dividendo are greek words. According to it,

If a/b = c/d , then (a+b) / (a-b) = (c+d) / (c-d).

Let me give you proof for the above statement.

Add 1 to both sides of the equation i.e., a/b + 1 = c/d + 1

(a+b) / b = (c+d) / d ….i)

Now, Subtract 1 from both sides of the equation i.e., a/b - 1 = c/d - 1

(a-b) / b = (c-d) / d ….ii)

Dividing eq. i) by ii). We get,

(a+b) / (a-b) = (c+d) / (c-d)

We use componendo and dividendo just to speed up the calculation part of the mathematics.

Kartik pandey

Last Activity: 7 Years ago

If a/b=c/d then we can say that a:b=c:d=k(universally recognised as costant).If a/b=c/d then a+b/a-b=c+d/c-d.By tranfering b on the other side we can say that a=kb,c=kd.A.T.Q kb+b/kb-b=kd+d/kd-dLets take LHS first:Lets take b common now we can say that b(k+1)/b(k-1) cancel out b fron numerator and denominator we obtain (k+1)/(k-1)RHS:kd+d/kd-d take d as common we can say that d(k+1)/d(k-1) .Cancel out d fron both numerator and denominator we obtain (k+1)/(k-1).LHS = (k+1)/(k-1)= RHS =(k+1)/(k-1).We conclude that LHS=RHS QED.