we have abc triangle angle A +angle B+angle C=180 when: 2 sin B=sin A +sin C prove that : tan(A/2) *tan(C/2)=1/3

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we have abc triangle angle A +angle B+angle C=180 when: 2 sin B=sin A +sin C prove that : tan(A/2) *tan(C/2)=1/3

we have abc triangle
angle A +angle B+angle C=180
when: 2 sin B=sin A +sin C
prove that : tan(A/2) *tan(C/2)=1/3

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we have abc triangle angle A +angle B+angle C=180 when: 2 sin B=sin A +sin C prove that : tan(A/2) *tan(C/2)=1/3

we have abc triangleangle A +angle B+angle C=180when: 2 sin B=sin A +sin Cprove that : tan(A/2) *tan(C/2)=1/3

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we have abc triangle
angle A +angle B+angle C=180
when: 2 sin B=sin A +sin C
prove that : tan(A/2) *tan(C/2)=1/3