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value of sin inverse sin x between -5pie by 2 to -3 pie by 2

Aditya , 8 Years ago
Grade 12
anser 1 Answers
Vijay Mukati

Last Activity: 8 Years ago

Dear Student,

The value of sin^(-1)sin (x) = x only if x lies between [-pi/2, pi/2]

But in your problem, x lies between [-5pi/2, -3pi/2] and thus we need to use reductin formula to bring this interval in the desired range. and thus we found that,

sin^(-1)sin(x) = 2pi + x, ifx lies between [-5pi/2, -3pi/2].

Best of luck!

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