two parallel chords are drawn on the same side of

Question

two parallel chords are drawn on the same side of the centre of circle of radius r. it is found that they subtend an angle of 2A and A at the centre of the circle. Then find the perpendicular distance between two chords

Sujit Kumar · Accepted Answer

Sorry the last Step is wrong in the above solution. The answer is Let The perpendicular distance from center to side opposite to angle A be xand the perpendicular distance from center to side opposite to angle 2A be x-yRequired to find:- The value of y Applying Trigonometory, On triangle with angle Ax=r(Cos\frac{A}{2}) src=http://latex.codecogs.com/gif.latex?Cos%5Cfrac%7BA%7D%7B2%7D%3D%20%5Cfrac%7Bx%7D%7Br%7D%3D%3Ex%3Dr%28Cos%5Cfrac%7BA%7D%7B2%7D%29 style=box-sizing: border-box; max-width: 100%; height: auto; vertical-align: middle; border: 0px;>__________(1) On triangle with angle 2Ax-y=r(CosA) src=http://latex.codecogs.com/gif.latex?CosA%3D%20%5Cfrac%7Bx-y%7D%7Br%7D%3D%3Ex-y%3Dr%28CosA%29 style=box-sizing: border-box; max-width: 100%; height: auto; vertical-align: middle; border: 0px;>__________(2) Subtracting Equation (2) from (1)

Trigonometry> two parallel chords are drawn on the same...

two parallel chords are drawn on the same side of the centre of circle of radius r. it is found that they subtend an angle of 2A and A at the centre of the circle. Then find the perpendicular distance between two chords

rehab , 7 Years ago

Sujit Kumar

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Trigonometry> two parallel chords are drawn on the same...

two parallel chords are drawn on the same side of the centre of circle of radius r. it is found that they subtend an angle of 2A and A at the centre of the circle. Then find the perpendicular distance between two chords

rehab , 7 Years ago

Sujit Kumar

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

Other Related Questions on trigonometry

In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.

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To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA

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cos^2 13ºcos^2 47º+cos^2 73º =? …..................

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Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)

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