0

Guest

Courses New

two parallel chords are drawn on the same side of the centre of circle of radius r. it is found that they subtend an angle of 2A and A at the centre of the circle. Then find the perpendicular distance between two chords

two parallel chords are drawn on the same side of the centre of circle of radius r. it is found that they subtend an angle of 2A and A at the centre of the circle. Then find the perpendicular distance between two chords

Grade:11

1 Answers

Sujit Kumar
111 Points
6 years ago
y=r(Cos\frac{A}{2}-CosA)Sorry the last Step is wrong in the above solution. The answer is 
Let The perpendicular distance from center to side opposite to angle A be x
and the perpendicular distance from center to side opposite to angle 2A be x-y
Required to find:- The value of y
 
Applying Trigonometory,
 
On triangle with angle A
Cos\frac{A}{2}= \frac{x}{r}=>x=r(Cos\frac{A}{2})__________(1)
 
On triangle with angle 2A
CosA= \frac{x-y}{r}=>x-y=r(CosA)__________(2)
 
Subtracting Equation (2) from (1)
 
y=r(Cos\frac{A}{2}-CosA)
Ans: \ The \ perpendicular \ distance \ between \ the \ two \ parallel \ chords \ is \ r(Cos\frac{A}{2}-CosA)
 

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More