Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Trigonometric ratios and identities...these two questions in the image...please help

Trigonometric ratios and identities...these two questions in the image...please help

Question Image
Grade:11

1 Answers

Faiz
107 Points
4 years ago
19. (x + z) / 2 = y as x, y, z are in APUsing identities sinC - sinD in numerator and cos C - cosD in denominator, the expression becomes:Numerator: 2 cos[ (x + z) / 2 ] sin[ (x - z) / 2 ]Denominator: 2 sin[ (x + z) / 2 ] sin[ (x - z) / 2 ]Replace (x+z)/2 by y and divide them as 2 and sin[ (x - z) / 2 cancel out leaving behind cot yAns: cot y20. Let the given expression be equal to k.x= k cos py= k cos (p - 2π/3)z= k cos (p + 2π/3)Adding all:x+y+z = k[ cos p + cos (p - 2π/3) + cos (p + 2π/3) ]Using cosC + cosDx+y+z = k[ cos p + 2 cos p cos 2π/3 ]x+y+z = k[ cos p + 2 cos p (-1/2) ]x+y+z = k[ cos p - cos p]Ans: x+y+z = 0

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free