Triangle ABC has angle B is 90° the point O is with in the tringle where angle AOC= angle COB =angle BOA =120. X is the angle OBC calculate tan X =[c+a√(3)]/[a+c√(3)]
Triangle ABC has angle B is 90° the point O is with in the tringle where angle AOC= angle COB =angle BOA =120. X is the angle OBC calculate tan X =[c+a√(3)]/[a+c√(3)]











