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Grade: 12th pass
Triangle ABC has angle B is 90° the point  O is with in the tringle where angle AOC= angle COB =angle BOA =120. X is the angle OBC calculate tan X =[c+a√(3)]/[a+c√(3)]
one year ago

Answers : (1)

Aditya Gupta
1806 Points
this ques is directly based on sine rule and is exceptionally easy.
apply sine rule in triangle AOB and BOC successively.
sin(theta – 30)/OB= sin120/c
and sin120/a= sin(60 – theta)/OB
eliminate OB, apply componendo and dividendo on sin(60 – theta)/sin(theta – 30).
then simply obtain tan(theta) by standard formula (as you will already have the equation in form of tan(45 – theta))
9 months ago
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