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`        Triangle ABC has angle B is 90° the point  O is with in the tringle where angle AOC= angle COB =angle BOA =120. X is the angle OBC calculate tan X =[c+a√(3)]/[a+c√(3)]`
one year ago

1806 Points
```							this ques is directly based on sine rule and is exceptionally easy.apply sine rule in triangle AOB and BOC successively.sin(theta – 30)/OB= sin120/cand sin120/a= sin(60 – theta)/OBeliminate OB, apply componendo and dividendo on sin(60 – theta)/sin(theta – 30).then simply obtain tan(theta) by standard formula (as you will already have the equation in form of tan(45 – theta))
```
9 months ago
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Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions