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This is a question from the chapter trigonometry. Can any one solve it.
This is a question from the chapter trigonometry. Can any one solve it.

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2 years ago

54 Points
```							In this question the need is to simplify both the equations first individually and then after certain amount of simplfication equating both of them.STEP 1Divide the first equation throughout by cos2$\dpi{50} \LARGE \Theta$.Then, the equation will be:a tan2$\dpi{50} \LARGE \Theta$ + b = m(1 + tan2$\dpi{50} \LARGE \Theta$)By, simplyfication:(a – m) tan2$\dpi{50} \LARGE \Theta$ = m – b.......(3)STEP 2Divide the first equation throughout by cos2$\dpi{50} \LARGE \Phi$.Then, the equation will be:b tan2$\dpi{50} \LARGE \Phi$ + a = n(1 + tan2$\dpi{50} \LARGE \Phi$)By, simplyfication:(b – n) tan2$\dpi{50} \LARGE \Phi$ = n-a ........(4)STEP 3Simplification of condition given:a tan$\dpi{50} \LARGE \Theta$ = b tan$\dpi{50} \LARGE \Phi$tan2$\dpi{50} \LARGE \Theta$/tan2$\dpi{50} \LARGE \Phi$ = b2/a2…......(5)STEP 4Divide equations (3) and (4), then inject the equation (5) in the new equation:(a – m)(b2)(n – a) = (m – b)(a2)(b – n) ab2n – mnb2 – a2b2 + amb2 = amb2 – a2mn – a2b2 + a2bn ab2n + a2mn – mnb2 – nba2 = 0 a2n(m – b) + b2n(a – m) = 0 a2n (m – b)= b2n(m – a) THE FINAL EQUATION IS: a2/b2=(m-b)/(m-a)
```
2 years ago
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• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions