Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        this is a question asked in mca entrance..i m nt able to tackle it in easy way...kindly help`
one year ago

Anish Singhal
1195 Points
```							Its quite simple just apply chain rule after simplifying the given expression(use basic formulas of trigonometry)
```
one year ago
Rajat
213 Points
```							y'=2sinacosa-2sin(a+b)cos(a+b)+2sinb[cosacos(a+b)-sinasin(a+b)]=sin2a-sin2(a+b)+2sinbcos(2a+b)=sin[(2a+b)-b] - sin[(2a+b)+b] + 2sinbcos(2a+b)= -2sinbcos(2a+b) + 2sinbcos(2a+b)= 0 So, y'''=0 Please approve and best of luck
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions