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the value of tan(A/2)[(1+secA)(1+sec2A)(1+sec4A)(1+sec8A)......(1+sec2nA)] is
convert tan(A/2) into sin/cos form1+secA=2cos2(A/2)/cosA1+sec2A=2cos(A)/cos2A...and 2Sin(A/2)cos(A/2) becomes sinAand convert all into same form simplify it you will getthe final answer as Tan2nA
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