The value of cosec10°– 3 sec10° is : what`s the answer

I think the expression should be cosec10° - √3 sec10°.-> 1/sin10° - √3/cos 10°-> (cos10° - √3 sin 10°) / sin 10° cos 10 °Multiplying and dividing by 2 in numerator and denominator both:-> 4 ( cos10° / 2 - √3 sin 10° / 2 ) / 2 sin10 ° cos 10°-> 4 ( sin30° cos 10° - cos 30° sin 10° ) / sin 20°-> 4 sin ( 30 - 10 )° / sin 20°-> ans: ....... 4Identity used is sin 2x = 2 sinx cosxAnd sin (x-y) = sinx cos y - cos x sin y.