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`        The question is (a square-b square)sinAsinB divided by two sin( A-B) is equal to`
2 years ago

```							= (a2-b2)sinAsinB/2sin(A-B)= (a2-b2) ab/ 4R2 2sin(A-B)     [a/sinA=b/sinB=2R]= (a2-b2) ab/ 4R2 [sinAcosB-sinBcosA]= (a2-b2) ab/ 4R2 [a(a2+c2-b2)/ 2R(2ac) – b (b2+c2-a2)/ 2R(2bc)]=(a2-b2) ab/ R [(a2+c2-b2)- (b2+c2-a2)/c]=(a2-b2) abc/ R [2(a2-b2)]= abc/2R      [abc=4Rdelta] = 2delta so the answer is 2 delta
```
2 years ago
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