The number of real solutions of the equation (Tan inverse root of(x^2-3x+2)) + (Cos inverse root of (4x-x^2-3)) = Pi

Since under root of any number is a positive number hence both inverse will lie in 0 to pi/2. But for them to add upto pi, it is NOT POSSIBLE unless term under tan inverse is infinite, which is not possible for real x. Hence NO SOLUTION