badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

The minimum value of atan 2 x + cot 2 x equals the maximum value of asin 2 y + bcos 2 y where a and b are grater than 0. Then a/b is (a)2 (b)4 (c)6 (d)8 Please explain fully.

4 years ago

Answers : (2)

Vikas TU
13783 Points
							
Minimum value of atan2x + cot2x = >
First convert them into sec and cosec.
= a(sec^2x – 1) + (cosec^2 – 1)
= a(1/cos^^2x – 1) + (1/sin^2x – 1)
= 1/sin^2x + a/cos^2x – 2
= 1/(1-cos^2x) + a/cos^2x –  2
Now here sin and cos values should be maximum for getting minmum values.
SO,
Min. value would be = > 1/(1-0) + a/1 – 2 => a – 1
 
Now maximum value of asin2y + bcos2 = > asin^2y +b – bsin^2y
=> b + [sin^2y]*(a – b)
=> b + a – b
=> a
4 years ago
Mudit
67 Points
							
The minimum value is 2√ab but I can not understand how it came?
 
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details