The given expression sec^2 x =4xy/(x+y)^2 is true if and only if : A) x+y not equal 0B) x=y and x not = 0C ) x=yD) x and y both not equal to 0

Question

Nishchal Joshi · Answer

Cosec2Ѳ = 4xy / (x+y)2 Let cosec2Ѳ has a real value Therefore, cosec2Ѳ ≥ 1 So, 4xy/(x+y)2 ≥ 1 or (x+y)2 ≤ 4xy or (x+y)2 - 4xy ≤ 0 or (x-y)2 ≤ 0 This implies that x=y Therefore given equation holds only if x=y

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The given expression sec^2 x =4xy/(x+y)^2 is true if and only if : A) x+y not equal 0B) x=y and x not = 0C ) x=yD) x and y both not equal to 0

The given expression sec^2 x =4xy/(x+y)^2 is true if and only if : A) x+y not equal 0B) x=y and x not = 0C ) x=yD) x and y both not equal to 0

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The given expression sec^2 x =4xy/(x+y)^2 is true if and only if : A) x+y not equal 0B) x=y and x not = 0C ) x=yD) x and y both not equal to 0

The given expression sec^2 x =4xy/(x+y)^2 is true if and only if : A) x+y not equal 0B) x=y and x not = 0C ) x=yD) x and y both not equal to 0

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