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The equation whose roots are tan^2 π/7, tan^2 3π/7 and tan^2 5π/7 is
The equation whose roots are tan^2 π/7, tan^2 3π/7 and tan^2 5π/7 is

```
4 years ago

Saurabh Koranglekar
10341 Points
```							Let x^3 + bx^2 + cx+d = 0 be the equationb = -(tan^2 π/7 + tan^2 3π/7  +  tan^2 5π/7) ;c= ( 2*tan^2 π/7 * tan^2 3π/7 + 2 *tan^2 3π/7 *tan^2 5π/7 + 2 *tan^2 2π/7 *tan^2 5π/7) ;d = – (tan^2 π/7* tan^2 3π/7 * tan^2 5π/7);using trigonometric identity you can simplify
```
2 years ago
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• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions