the equation of √3 sin x + cosx = 1+k is solvable only if k is in interval (a) (-3,1) (b) (-2,3) (c) [-2,3] (d) [-3,1]

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Amit · Answer

Hi there.. You can see that maximum value of the function is 2 and minimum is -2 .. It can accordingly be equated to 1+ k to get maximum and minimum value of k.. Option D will match.

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the equation of √3 sin x + cosx = 1+k is solvable only if k is in interval (a) (-3,1) (b) (-2,3) (c) [-2,3] (d) [-3,1]

the equation of √3 sin x + cosx = 1+k
is solvable only if k is in interval
(a) (-3,1)
(b) (-2,3)
(c) [-2,3]
(d) [-3,1]

the equation of √3 sin x + cosx = 1+k

1 Answers

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the equation of √3 sin x + cosx = 1+k is solvable only if k is in interval (a) (-3,1) (b) (-2,3) (c) [-2,3] (d) [-3,1]

the equation of √3 sin x + cosx = 1+kis solvable only if k is in interval(a) (-3,1)(b) (-2,3)(c) [-2,3](d) [-3,1]

the equation of √3 sin x + cosx = 1+k

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the equation of √3 sin x + cosx = 1+k
is solvable only if k is in interval
(a) (-3,1)
(b) (-2,3)
(c) [-2,3]
(d) [-3,1]