The eq. (cosp - 1)x2 +cospx +sinp = 0 where x is a variable, has real roots. then the interval of p is........................

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The eq. (cosp - 1)x2 +cospx +sinp = 0 where x is a variable, has real roots. then the interval of p is........................

The eq. (cosp - 1)x2 +cospx +sinp = 0 where x is a variable, has real roots. then the interval of p is........................

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The eq. (cosp - 1)x2 +cospx +sinp = 0 where x is a variable, has real roots. then the interval of p is........................

The eq. (cosp - 1)x2 +cospx +sinp = 0 where x is a variable, has real roots. then the interval of p is........................

1 Answers

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Other Related Questions on Trigonometry

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