Aditya Gupta
Last Activity: 6 Years ago
Let height of tower be h and base of tower be called O. Also, let CO= y, BC=3x which implies AB= 4x.
Then tanb= h/(7x+y), tan2b= h/(3x+y) and tan3b= h/y. We also know that tan2b and tan3b are expressible in terms of tanb. Thus after elimination of all parameters but b, you shall obtain the equation:
12/7= 1+tan^2b= sec^2b
So sinb=√(1-7/12)
= √(5/12)