The angle of elevation of a tree at a place 80 m away is 12 degree 5 min.What is the height of a tree?

Question

Vikas TU · Answer

theta = 12 degrees 5 mins Height is h . Distance is 80m According to question a right angled triangle is formed Tan theta = h/d Tan theta = h/80 0.2144 * 80 = h h=17.152 m. This would be the height of the tree.

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The angle of elevation of a tree at a place 80 m away is 12 degree 5 min.What is the height of a tree?

The angle of elevation of a tree at a place 80 m away is 12 degree 5 min.What is the height of a tree?

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The angle of elevation of a tree at a place 80 m away is 12 degree 5 min.What is the height of a tree?

The angle of elevation of a tree at a place 80 m away is 12 degree 5 min.What is the height of a tree?

1 Answers

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