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Grade 12th passTrigonometry

Tell me the easy trick to slove the value of cos37,cos53,sin37,sin53

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Profile image of shikhagupta
9 Years agoGrade 12th pass
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1 Answer

Profile image of ayushi jaimani
9 Years ago
the easiest trick to remeber anything is to make a pattern out of the problem nd same goes here,
cos37=4/5
cos53=3/5       inverse of cos37=sin53
                        inverse of cos53=sin37
sin37=5/4
u can also calculate these values ueself , cz this way the best.
sin53=4/5