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tanx+tan(π+π/4)=2 find the most general value of x satisfying the given equation. tanx+tan(π+π/4)=2 find the most general value of x satisfying the given equation.
tan(π+π/4)=1,so we get tanx=2-1=1,or tanx=tan(π/4),or x=nπ+π/4, where n belongs to integer, which is the general solution
Dear Gulshan tan x + tan pi/4 = 2 tan x = 2 – 1 tan x = 1 hence x = n * pi + pi/4 RegardsArun (askIITians foryum expert)
Given,TanX+Tan(π+π/4)=2Tan( π+π/4)=1,As we know that Tan(π+π/4)= 1ThenTanX+1=2 TanX=2-1 =1TanX =1 it satisfy'' only when X value is 45. Because Tan45=1
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