Grade 11Trigonometry
tanx+tan(π+π/4)=2 find the most general value of x satisfying the given equation.
tanx+tan(π+π/4)=2 find the most general value of x satisfying the given equation.
3 Answers
Aditya Gupta
tan(π+π/4)=1,
so we get tanx=2-1=1,
or tanx=tan(π/4),
or x=nπ+π/4, where n belongs to integer, which is the general solution
Arun
Dear Gulshan
tan x + tan pi/4 = 2
tan x = 2 – 1
tan x = 1
hence
x = n * pi + pi/4
Regards
Arun (askIITians foryum expert)
Yash
Given,
TanX+Tan(π+π/4)=2
Tan( π+π/4)=1,
As we know that Tan(π+π/4)= 1
Then
TanX+1=2
TanX=2-1
=1
TanX =1 it satisfy'' only when X value is 45. Because Tan45=1
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