×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# TanA+sinA=m and tanA_sinA=n show that (m^2-n^2)=16mn

2 years ago

Arun
25768 Points

m = tanA + sinA
n = tanA - sinA
L.H.S. = {(tanA + sinA)² - (tanA-sinA)²}
{tan²A + sin²A + 2tanAsinA - (tan²A + sin²A - 2tanAsinA)}²
⇒ = (4tanAsinA)²
16tan²Asin²A
16tan²A(1 - cos²A)
16tan²A - tan²Acos²A
16tan²A - sin²A/cos²A × cos²A
16tan²A - sin²A
16(tan²A + sin²A) (tan²A - sin²A)
= 16 mn
2 years ago
Deepak Kumar Shringi
4404 Points

2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions