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TanA+sinA=m and tanA_sinA=n show that (m^2-n^2)=16mn TanA+sinA=m and tanA_sinA=n show that (m^2-n^2)=16mn
m = tanA + sinAn = tanA - sinAL.H.S. = {(tanA + sinA)² - (tanA-sinA)²}{tan²A + sin²A + 2tanAsinA - (tan²A + sin²A - 2tanAsinA)}²⇒ = (4tanAsinA)²16tan²Asin²A16tan²A(1 - cos²A)16tan²A - tan²Acos²A16tan²A - sin²A/cos²A × cos²A16tan²A - sin²A16(tan²A + sin²A) (tan²A - sin²A)= 16 mn
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