tanA + secA -1 / tanA -secA + 1 = 1 +sinA / cosAI would like to get answer for this question in trigonometry
tanA + secA -1 / tanA -secA + 1 = 1 +sinA / cosA
I would like to get answer for this question in trigonometry
n , 8 Years ago
Grade 10
Trigonometry> tanA + secA -1 / tanA -secA + 1 = 1 +sinA...
2 AnswersNandana
hi ,
tanA + secA -1 / tanA -secA + 1 = (sinA +1-cosA) /(sinA+cosA-1 ) × (sinA+cosA +1)/(sinA+cosA+1)
= (sinA+cosA )(sinA-cosA)+sinA+cosA-cosA+1+sinA-cosA/(sinA+cosA)2-12)
after simplification this is equal to
= 2sinA(1+sin A)/ 2sinA cosA
= (1+sin A)/ cosA
hence right side obtainnd
Kushagra Madhukar
Dear student,
Please find the answer to your question below.
tanA + secA – 1 / tanA – secA + 1 = (sinA + 1 – cosA) / (sinA + cosA – 1) × (sinA + cosA + 1) / (sinA + cosA + 1)
= (sinA + cosA )(sinA – cosA) + sinA + cosA – cosA + 1 + sinA – cosA / (sinA + cosA)2 – 12)
On simplifying, we get,
= 2sinA(1 + sin A) / 2sinAcosA
= (1 + sin A) / cosA
LHS = RHS
Hence proved.
Hope it helps.
Thanks and regards,
Kushagra
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