Grade 11Trigonometry
tanA/2=underroot1-e/1+e * tanB/2,then cosB=?
tanA/2=underroot1-e/1+e * tanB/2,then cosB=?
1 Answer
Arun Kumar
Hello Student,
tanA/2=root(1-e/1+e) * tanB/2
Use this formulae
cos2A=(1-tan^2A)/(1+tan^2A)
you should be done after that easily.
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
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