1800-150-456-789
FlagBACK
Flag Trigonometry> tanA/2=underroot1-e/1+e * tanB/2,then cos...
question mark

tanA/2=underroot1-e/1+e * tanB/2,then cosB=?

Abhinav Acharya , 10 Years ago
Grade 11
anser 1 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello Student,
tanA/2=root(1-e/1+e) * tanB/2
Use this formulae
cos2A=(1-tan^2A)/(1+tan^2A)
you should be done after that easily.
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...

Other Related Questions on Trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
Trigonometry
1 Answer Available

Last Activity: 2 Year ago(s)

question mark
\tFind the general solution of equation tan3∂=cot2∂For all angles between -720 and +720
Trigonometry
0 Answer Available

Last Activity: 2 Year ago(s)

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
Trigonometry
0 Answer Available

Last Activity: 2 Year ago(s)

question mark
cos^2 13ºcos^2 47º+cos^2 73º =? …..................
Trigonometry
0 Answer Available

Last Activity: 2 Year ago(s)

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
Trigonometry
0 Answer Available

Last Activity: 2 Year ago(s)