Grade 10Trigonometry
TanA=1\2 TanTanB=1\3 to Tan(2A+B)tatha Tan(2A-B) ka man gyat keejiye
TanA=1\2 TanTanB=1\3 to Tan(2A+B)tatha Tan(2A-B) ka man gyat keejiye
1 Answer
Arun
tan(A+B)= (tanA+tanB)/ (1-tanA tan B)
tan2A= 2tanA / 1-tan^2A
tan2A= 2tanA / 1-tan^2A
Use these formulas
You will clear get your answer
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