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Grade: 10

                        

Tan75+tan15/1-tan75×tan15 please answer this question...I need the answer fast. Thanks whoever answers.

3 years ago

Answers : (1)

Shailendra Kumar Sharma
188 Points
							
) We can relate it to (Tan75+tan15)/(1-tan75×tan15 (TanA+tanB)/(1-tanA×tanB) =tan(A+B)
So ) =Tan (75+15) =tan90 =infinity  (Tan75+tan15)/(1-tan75×tan15 
 
3 years ago
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