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Grade: 10
        tan60°-tan30°---------------------=tan30°1+tan60°. tan30°
2 years ago

Answers : (4)

CHAKRAVARTHI
52 Points
							
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2
2 years ago
CHAKRAVARTHI
52 Points
							
 
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2
2 years ago
CHAKRAVARTHI
52 Points
							
 
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2
 
2 years ago
CHAKRAVARTHI
52 Points
							
 
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2
 
 
2 years ago
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  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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