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tan60°-tan30°---------------------=tan30°1+tan60°. tan30°

Vishal kumar , 7 Years ago
Grade 10
anser 4 Answers
CHAKRAVARTHI

Last Activity: 7 Years ago

Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2

CHAKRAVARTHI

Last Activity: 7 Years ago

 
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2

CHAKRAVARTHI

Last Activity: 7 Years ago

 
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2
 

CHAKRAVARTHI

Last Activity: 7 Years ago

 
Answer is” tan-1[1+ square root of 3] /2
Given ,
 = tan600-[tan300][X]=tan300+tan600.tan300
=square root of 3-1/ square root of 3[X]=1/ square root of 3+[ square root of 3.1/ square root of 3]  …. [CANCEL]
=[3-1] / square root of 3[X]=1/ square root of 3 +1
=finally we get,
 X =[1+ square root of 3] /2
 
 

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