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Grade 11Trigonometry

Tan3A = 4 , then Sin3A = ?
TanA SinA
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Profile image of Prabhav Sharma
9 Years agoGrade 11
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1 Answer

Profile image of Saurabh Koranglekar
6 Years ago
Dear student

Tan X = perpendicular/ base

Sin x = perpendicular/ hypotenuse

Sin3 A = 4 / sqrt( 17)

Regards

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