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tan A = xsinB/1-xcasB, tanB =ysinA/1-ycosA, prove that sinA/sinB=x/y

tan A = xsinB/1-xcasB, tanB =ysinA/1-ycosA, prove that sinA/sinB=x/y

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1 Answers

Sankalp Das
25 Points
3 years ago
tanA=xsinB/(1-xcosB).......Cross multiply..... tanA-xcosBtanA=xsinB......X=tanA/(sinB+cosBtanA)......X=sinA/cosA{(sinBcosA+sinAcosB)}/cosA......On solving we get x=sinA/sin(A+B)...(1)...Similarly y=sinB/sin(B+A)....(2)....... Dividing (1)/(2) we get x/y=sinA/sinB

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