tan A = xsinB/1-xcasB, tanB =ysinA/1-ycosA, prove that sinA/sinB=x/y
Sudipta Roy , 6 Years ago
Grade
Trigonometry> tan A = xsinB/1-xcasB, tanB =ysinA/1-ycos...
1 AnswersSankalp Das
Last Activity: 6 Years ago
tanA=xsinB/(1-xcosB).......Cross multiply..... tanA-xcosBtanA=xsinB......X=tanA/(sinB+cosBtanA)......X=sinA/cosA{(sinBcosA+sinAcosB)}/cosA......On solving we get x=sinA/sin(A+B)...(1)...Similarly y=sinB/sin(B+A)....(2)....... Dividing (1)/(2) we get x/y=sinA/sinB
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