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```
(tan a +sec a - 1) (tan a + 1 +sec a) =2 sin a/ 1 - sin a

```
2 years ago

Arun
25768 Points
```							tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cos Amultiply LHS by cosA /cosA to get (sinA+1-cosA) / (sinA-1+cosA) multiply again by cosA/cosA to get (sinA.cosA+cosA-cos^2A) / cosA(sinA-1+cosA) = ( cosA(1+sinA) - (1-sin^2A) ) / cosA(sinA-1+cosA) = ( cosA(1+sinA) - (1+sinA)(1-sinA) ) / cosA(sinA-1+cosA) = ( (1+sinA)(cosA-1+sinA) ) / cosA(sinA-1+cosA) = (1+sinA)/cosA RegardsArun
```
2 years ago
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