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`        Tan(45-A/2)+tan(45+A/2)=4/√3 then the general solution is`
4 months ago

Rajat
213 Points
```							tan(45+A/2) = (1+tanA/2)/(1-tanA/2)tan(45-A/2) = (1-tanA/2)/(1+tanA/2)Let,tan(45+A/2) = xSo,x + 1/x = 4/√3Or, √3x^2-4x+√3=0So, x = √3, 1/√3Hence, tan(π/4+A/2) = tan (nπ+ π/3) or tan(nπ+π/6)1) π/4+A/2 = nπ+π/3 Or A= 2nπ+π/62) π/4+A/2 = nπ +π/6Or A =2nπ-π/6Thus option A is correct
```
4 months ago
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