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tan (3pi/16) + cot (3pi/16)= (1)√(√2-1) (2)2√(√2-1) (3) 2 3/4 √(√2-1) (4)2 5/4 √(√2-1)

tan (3pi/16) + cot (3pi/16)=
(1)√(√2-1)   (2)2√(√2-1)   (3) 23/4√(√2-1)    (4)25/4√(√2-1)

Grade:12

1 Answers

Yogendra Kumar
askIITians Faculty 117 Points
2 years ago
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