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Grade: 12
        
tan^2 x+tan^2 y+ tan^2 z =1 then what is the maximum value of 3 tanx 4ta y+ 5 tanz?
one year ago

Answers : (2)

SanchiSSonawane
16 Points
							Since t
						
one year ago
SanchiSSonawane
16 Points
							
solution: tanx= tany=tanz=1/√3
then 3/√3 .4/√3 + 5/√3=12/3 + 5/√3=4+5/√3
therefore the answer is 4+5/√3
one year ago
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