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Grade 10Trigonometry

solve the following identities : 1) 1+cot²0/1+cosec0=cosec0
2)1+tan²0/sec0+1=sec0
3)sin0(1+tan0)+cos0(1+cot0)=sec0+cosec0
?4)(1+tan²0)cot0/cosec²0=tan0

please explain me in steps.

kaushik kashyap

12 Years agoGrade 10

2 Answers

Rinkoo Gupta

12 Years ago

1+cot²ß/1+cosecß=cosecß

Cosec²ß/1+cosecß=cosecß

Cosec²ß=cosecß+cosec²ß

Cosecß=0

Sinß=8

ð No solution.

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

Arun Kumar

12 Years ago

Hi

I'll solve the first question only for rest make another post and post only one question in one post.

$\\\frac{1+cot^2\theta}{1+cosec\theta} \\\frac{sin^2\theta+cos^2\theta}{(1+cosec\theta)sin^2\theta} \\$see if $ (1+cosec\theta) $ would have been just $ cosec\theta $ it would be a correct expression$ \\So \\=>\frac{1+cot^2\theta}{cosec\theta}=cosec\theta$

$\\1+cot^2\theta=cosec^2\theta+cosec\theta \\=>cosec\theta=0 \\$which isn't possible$$

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

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