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solve the following equation for x tan^-1(2x) +tan^-1(3x) = n(pi) + 3pi/4
tan-1(2x) +tan-1(2y)= n(pi) +3pi/4tan-1{(2x+3x)/(1-2x.3x)}=n(pi)+3pi/45x/(1-6x2)=tan(npi+3pi/4)5x/(1-6x2)=tan3pi/4=tan(pi-pi/4)=-tanpi/4=-15x=-1+6x26x2-5x-1=0x=1,-1/6Thanks & RegardsRinkoo GuptaaskIITians Faculty
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