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Grade: 11
        
solve tan x+tan(x+60)+tan(x+120)=3.pls answer this question in detail.
 
2 years ago

Answers : (1)

Arun
23834 Points
							
Dear Prem
 
In RHS, it should 3 tan3A
Solution
 
 

Just expand the function ..

 

 

 

Tan A +  (tan 60 + tan A )/(1-tan60.tanA) +  (tan (120) + tan A )/(1-tan120.tanA)

 

 

 

tan A +  [root(3) + tanA]/[1-root(3).tanA] + [ tan A - root(3) ] /[1 + root(3).tanA]

 

 

 

tanA +  [ root(3) + 3.tanA + tanA + root(3).tan^2A  + tanA - root(3) -root(3).tan^2A + 3.tanA ] / [ 1 - 3tan^2A ]

 

 

 

tanA + [ 8tanA] / [ 1-3tan^2A ]

 

 

 

[9tanA - 3.tan^3A ]/[1-3tan^2A]

 

 

 

= 3.tan3A   ( eqaul to RHS )

 

 

 

Hence proved

 

 

 

Regards

Arun(askIITians forum expert)

2 years ago
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